Case study question please solve Share with your friends Share 0 Atul Shaw answered this Dear student,3. For checking Pythagoras triplet, choose the maximum number among them as hypotenuse and other two as base and perpendicular, then usePythagoras theorem and verify it.a. 7,24,25h=25let p=7 and b=24p2+b2=72+242=625h2=252=625as, p2+b2=h2 thus it is Pythagorean triplet.b. 15,8,17h=17let p=15 and b=8p2+b2=152+82=289h2=172=289as, p2+b2=h2 thus it is Pythagorean triplet.c. 5,12,13h=13let p=12 and b=5p2+b2=122+52=169h2=132=169as, p2+b2=h2 thus it is Pythagorean triplet.d. 21,20,28h=28let p=21 and b=20p2+b2=212+202=841h2=282=784as, p2+b2≠h2 thus it isnot a Pythagorean triplet.Option D is correct.For further queries, please start a new thread to get rapid assistance from our experts.Regards 0 View Full Answer Garima Shukla answered this 1) b 0
