CH3CHO+2H^++2e^--->Ch3CH2OH the half cell potential is -0.197V pH=7.calculate the half cell potential when pH is 6 and ethanol and acetaldehyde each has concentration 10^-5M Share with your friends Share 2 Geetha answered this According to Nernst equationE= E0 - 0.0591n log [oxidised][reduced]-0.197 = E0 - 0.0591n log [oxidised][reduced] = E0- 0.05912 log [1][H+]2 E0 = -0.197 + 0.05912 log [1][H+]2 = -0.197 + 0.05912 log H+-2 = -0.197 - 0.05912 2 log H+ = -0.197 +0.0591 × pH = -0.197 +0.0591 × 7 = 0.2167Using this value E= 0.2167 - 0.05912 log [1][H+]2 = 0.2167 - 0.05912 log H+-2 = 0.2167 + 0.05912 2 log H+ = 0.2167 - 0.05911 pH = 0.2167 - 0.0591× 6 = -0.1379 5 View Full Answer
