change in volume when 100 ml PH3 decomposed to solid p &H2gas.

  1. increase in 50 ml
  2. decrease in 50 ml
  3. increase in 150 ml
  4. decrease in 200 ml

The reaction can be written as follows:
2PH3 (g)  →  2P (s)  + 3H2 (g)
2 moles of Phosphine produces 3 moles of Hydrogen gas or we can say that
2 volume of phosphine produces 3 volume hydrogen gas
100 mL  of phosphine will produce 32×100 mL of Hydrogen gas

= 150 mL
Change in volume of gas = 150 - 100
= 50 mL
There is increase in volume of hydrogen gas by 50 mL. Thus, the correct option is (a).
 

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