change in volume when 100 ml PH3 decomposed to solid p &H2gas.
- increase in 50 ml
- decrease in 50 ml
- increase in 150 ml
- decrease in 200 ml
The reaction can be written as follows:
2PH3 (g) → 2P (s) + 3H2 (g)
2 moles of Phosphine produces 3 moles of Hydrogen gas or we can say that
2 volume of phosphine produces 3 volume hydrogen gas
100 mL of phosphine will produce
= 150 mL
Change in volume of gas = 150 - 100
= 50 mL
There is increase in volume of hydrogen gas by 50 mL. Thus, the correct option is (a).
2PH3 (g) → 2P (s) + 3H2 (g)
2 moles of Phosphine produces 3 moles of Hydrogen gas or we can say that
2 volume of phosphine produces 3 volume hydrogen gas
100 mL of phosphine will produce
= 150 mL
Change in volume of gas = 150 - 100
= 50 mL
There is increase in volume of hydrogen gas by 50 mL. Thus, the correct option is (a).