Charges of + 15pC, - 15pC,+ 20pC and 50pC are placed in order at each of the corners - Physics - Electric Charges And Fields

Question

Charges of + 15pC, - 15pC,+ 20pC and – 50pC are placed in
order at each of the corners of a square of a side 20cm Calculate
the intensity of electric field at the point of intersection of the
diagonals ​

Ved Prakash Lakhera · Accepted Answer

Let charges +15pC, -15pC, +20pC and -50pC are placed at corners A, B, Cand D corners of a square
 the distance of points A, B, C and D from the point O which is the point of intersection of diagonals of a square, is;                    OA=OB=OC=OD=202 ×10-42=102 ×10-4=2 ×10-3mThe electric field in the direction of AC due to chrges +15pC and +20pC is given by;                  E1=9×109×20-15×10-122 ×10-32=9×52×103=452×103N/CSimilarly the electric field in the direction of BD due to chrges +50pC and +15pC is given by;                  E2=9×109×50-15×10-122 ×10-32=9×352×103=3152×103N/CTherefore net electric field at O is given by;                  E=E12+E22 =4524+31524 =3225+1225               E=32×35
35=106 05/2=53
03N/CThe direction of this field intensity is      tanθ=45315=17or                                         θ=tan-117, where θ is the angle made by resultant intensity with the direction of E1

Charges of + 15pC, - 15pC,+ 20pC and – 50pC are placed in order at each of the corners of a square of a side 20cm. Calculate the intensity of electric field at the point of intersection of the diagonals. ​

Charges of + 15pC, - 15pC,+ 20pC and – 50pC are placed in order at each of the corners of a square of a side 20cm. Calculate the intensity of electric field at the point of intersection of the diagonals.