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Check whether 6*n*can end with the digit 0 for any natural number*n*.

Please find below the solution to the asked query:

To check whether ' 6

*n*' gives end ( units ) digit is ' 0 ' at

*n*= Any natural numbers ,

we know natural numbers : 1 , 2 , 3 , 4 , . . .

So,

*n*= 1 , 2 , 3 , 4 . . .

And we know 6 = 2 $\times $ 3

And we know 2 $\times $ 5 = 10

So when '

*n*' is multiple of ' 5 ' . We get ' 6

*n*' end digit is ' 0 ' .

At

*n*= 5 , 1 0, 15 , 20 , . . .

As at

*n*= 5

6

*n*= 6 $\times $ 5 = 30 , Here end digit is ' 0 ' .

Or at

*n*= 10

6

*n*= 6 $\times $ 10 = 60 , Here end digit is ' 0 ' .

Therefore,

**Yes , ' 6**

*n*' can give end digit ' 0 ' at*n*= 5 , 1 0, 15 , 20 , . . . . ( Ans )Hope this information will clear your doubts about topic.

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