Chem chem chemistry chem chem

Dear student!

Here given that, Final Pressure P₂ =1 atm , Initial pressure P₁ = 5 atm, T = 273 +25 = 298K, R = 8.314J/Kmol, n = 1mole

Now, We know that for, reversible expansion work done,

W = 2.2303 nRT log P₁ /P₂ 
     = 2.303 x 1 x 8.314 x298 ( log5 - log 1)
     = 5705.8 (0.69 -(-0))
     = 5705.8 x 0.69 
     = 3937.03 J

Regards,