Dear Student

Active Mass =
So,
Molar Mass of CO2 = 44 g/mol
Molar Mass of H2 = 2 g/mol
Molar Mass of N2 = 28 g/mol

​Given -
Mass of C2 = 22 g
Mass of H2 = 3 g
Mass of N2 = 7 g

We know,
No. of moles =
So,
Active Mass =

Let the volume of the gaseous mixture be 'V' litres

Active Mass of CO2 = $\frac{1}{2V}$ = $\frac{0.5}{V}$

Active Mass of ​H2 =  = ​$\frac{1.5}{V}$

Active Mass of N2 = $\frac{0.25}{V}$

Ratio will be 0.5 : 1.5 : 0.25 or 1 : 3 : 0.5

So, the correct option is (4).

Regards

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