Dear Student

Active Mass = No. of molesVolume inL
So,
Molar Mass of CO2 = 44 g/mol
Molar Mass of H2 = 2 g/mol
Molar Mass of N2 = 28 g/mol

​Given -
Mass of C2 = 22 g
Mass of H2 = 3 g
Mass of N2 = 7 g

We know,
No. of moles = MassMolar Mass 
So, 
Active Mass = MassMolar Mass x Volume in L

Let the volume of the gaseous mixture be 'V' litres
 
Active Mass of CO22244 x V = 12V = 0.5V

Active Mass of ​H2 = 32 x V = ​1.5V

Active Mass of N2728 x V = 0.25V

Ratio will be 0.5 : 1.5 : 0.25 or 1 : 3 : 0.5

So, the correct option is (4).

Regards
 

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