Chemistry question pls solve 1
Dear student,
From photoelectric effect , we can calculate the energy of one photon as:
E =hv = hc/ λ
Putting the values we get,
E = (6.62 x 10-34 Js x 3 x 108 m/s )/ 300 x 10 -9 m = 6.62 x 10-19 J
So, the energy for one mole of photons =6.62 x 10-19 x 6.022x 1023 = 3.99 x 105 J
Since, kinetic energy of electrons = 1.68 x 10 5J
So, minimum energy required to remove 1mole of electrons from sodium = (3.99 x 105 )- (1.68 x 105) = 2.31 x 105 J
Hence, minimum energy required to remove one electron = 2.31 x 105/ 6.022x 1023 =3.84 x 10-19 J
Now, wavelength , λ = hc/E = (6.62 x 10-34 Js x 3 x 108 m/s )/ 3.84 x 10-19 J = 5.17 x 10-7 m = 517 nm
Regards
From photoelectric effect , we can calculate the energy of one photon as:
E =hv = hc/ λ
Putting the values we get,
E = (6.62 x 10-34 Js x 3 x 108 m/s )/ 300 x 10 -9 m = 6.62 x 10-19 J
So, the energy for one mole of photons =6.62 x 10-19 x 6.022x 1023 = 3.99 x 105 J
Since, kinetic energy of electrons = 1.68 x 10 5J
So, minimum energy required to remove 1mole of electrons from sodium = (3.99 x 105 )- (1.68 x 105) = 2.31 x 105 J
Hence, minimum energy required to remove one electron = 2.31 x 105/ 6.022x 1023 =3.84 x 10-19 J
Now, wavelength , λ = hc/E = (6.62 x 10-34 Js x 3 x 108 m/s )/ 3.84 x 10-19 J = 5.17 x 10-7 m = 517 nm
Regards