Choose the correct option and explain The solution of CuSO4 in which copper rod is immersed is diluted - Chemistry - Electrochemistry

Question

Choose the correct option and explain

The solution of CuSO4 in which copper rod is immersed is
diluted to 10 times, the reduction electrode potential
1 increases by 0 030 V
2 decreases by 0 030 V
3 increases by 0 059 V
4 decreases by 0 059​V

Arun Dharavath · Answer

Nernst equation for CU2++2e−1→CuCU2++2e−1→Cu
is
E=E++0 0592E=E++0 0592log[cu2+]log⁡[cu2+]
By decreasing the conc of
Cu2+Cu2+ by 110,E110,E
will decrease by 0 05920 0592
(i e) approx by 0
03

Choose the correct option and explain. The solution of CuSO4 in which copper rod is immersed is diluted to 10 times, the reduction electrode potential 1. increases by 0.030 V 2. decreases by 0.030 V 3. increases by 0.059 V 4. decreases by 0.059​V

Choose the correct option and explain.

The solution of CuSO₄ in which copper rod is immersed is diluted to 10 times, the reduction electrode potential
1. increases by 0.030 V
2. decreases by 0.030 V
3. increases by 0.059 V
4. decreases by 0.059V