Chord PQ of parabola y^2 = x, where one end P of chord is at point (4,-2) is perpendicular to axis of parabola. Then slope of normal at Q is?

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Chord PQ of parabola y^2 = x, where one end P of chord is at point (4,-2) is perpendicular to axis of parabola. Then slope of normal at Q isWe havey2=xAs PQ is perpedicular to axis of parabola, hence PQis doubleordinateHence coordinate of Pis 4,-2 means coordinate of Q is 4,2y2=xDifferentiate with respect to x2y.dydx=1dydx=12ySlope of normal at Q=-dxdy4,2=-2y4,2=-2×2=-4 Answer

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