circular disc of mass 2 kg and radius 1 m is rotating about its axis perpendicular to its plane and passing through its centre of mass with a kinetic energy of 8J. the angular momentum in J-s is

Dear Student,

Kinetic energy of rotating body K.E. =12Iω28 =12mr2ω2=12212ω2ω2 =8ω=2.83Angular Momentum L = Iω =mr2ω=2122.83 =5.66 J.s
Hope this information will clear your doubts about topic.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

 
Regards    

  • -1
What are you looking for?