Circumference of the base of a cylinder, open at the top, is 132 cm The sum of radius and - Maths - Surface Areas and Volumes

Question

Circumference of the base of a cylinder, open at the
top, is 132 cm The sum of radius and height is 41 cm Find cost of
polishing the outer surface area of cylinder at the rate of Rs 10
per square decimeter ( Take Ï€ = 22/7 )

Sneha Mahajan · Accepted Answer

Circumference of the base = 132cm
2pie r = 132
2 (22/7)r = 132
r = 132*7 / 2*22
r = 21cm
Area to be polished = 2 pie r (r+h) - pie r2
= 2(22/7)(21)(41) - 22/7(21)2
= 5412 - 1386
= 4026cm2
= 4026/100 dm2
= 40 26 dm2
Cost of polishing 1dm2 area = Rs10
Cost of polishing 40 26 dm2 area = Rs 10 * 40 26 = Rs
402 60
Hope This Helps :)

Circumference of the base of a cylinder, open at the top, is 132 cm. The sum of radius and height is 41 cm. Find cost of polishing the outer surface area of cylinder at the rate of Rs. 10 per square decimeter. ( Take π = 22/7 )

Circumference of the base of a cylinder, open at the top, is 132 cm. The sum of radius and height is 41 cm. Find cost of polishing the outer surface area of cylinder at the rate of Rs. 10 per square decimeter. ( Take $π$ $=$ 22/7 )