compare average molar kinetic energies of He and Ar at 300K 1)K(He)=K(Ar) 2)K(He)>K(Ar) 3)K(He)=1/2K(Ar) Share with your friends Share 1 Vartika Jain answered this Dear Student, Average molar kinetic energy, K= 32RTFor He, K(He)= 32R×300For He, K(Ar)= 32R×300Therefore, K(He)K(Ar)=32R×30032R×300or, K(He)=K(Ar)Therefore, correct answer is (1) -1 View Full Answer Dishank Gupta answered this 2) option is correct 0