compare average molar kinetic energies of He and Ar at 300K
1)K(He)=K(Ar)
2)K(He)>K(Ar)
3)K(He)=1/2K(Ar)

Dear Student,

Average molar kinetic energy, K= 32RTFor He, K(He)= 32R×300For He, K(Ar)= 32R×300Therefore, K(He)K(Ar)=32R×30032R×300or, K(He)=K(Ar)Therefore, correct answer is (1) 

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2) option is correct
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