Compare the absolute values of the rational numbers in the following pairs:

(a)3/-7,-3/7 (b)-5/7,4/3 (c)-4/5,-3

Answer:
We know the absolute value of any number is the distance from the origin ( 0 ) on the number line ,
So we find the value of | a | to find the distance from the origin.

a) $\frac{3}{-7}$ , $\frac{3}{7}$
Now to find absolute value we find mode of both rational numbers as:
| $\frac{3}{-7}$ | =  $\frac{3}{7}$

| $\frac{3}{7}$ | = $\frac{3}{7}$
So comapirison of absolute value of $\frac{3}{-7}$ , $\frac{3}{7}$ is

$\frac{3}{7}$ = $\frac{3}{7}$                                                                   ( Ans )

b ) $\frac{-5}{7}$ , $\frac{4}{3}$
So absolute values are as:

| $\frac{-5}{7}$ | = $\frac{5}{7}$


| $\frac{4}{3}$ |  = $\frac{4}{3}$ 

So comparison

$\frac{5}{7}$  <  ​$\frac{4}{3}$                                             ( Ans )

c) $\frac{-4}{5}$ , -3
So absolute values are as:

| $\frac{-4}{5}$ | = $\frac{4}{5}$

| - 3 | = 3

$\frac{4}{5}$  <   3                   ( Ans )