Compound A with molecular formula C4H9Br is treated with aqueous KOH solution. The rate of reaction depends on concentration of A only. When another optically active isomer B is treated with aqueous KOH the rate or reaction is found to depend on B and OH–. Write down formulas of A and B. Out of these two compounds which would be converted to inverse configuration and racemisation?
A is 2-Bromo-2-methylpropane. It will follow Sn1 nucleophilic substitution mechanism as it is a tertiary molecule.
B is 2-bromobutane, an optically active compound. It will follow Sn2 nucleophilic substitution mechanism and the molecule will undergo inversion.
B is 2-bromobutane, an optically active compound. It will follow Sn2 nucleophilic substitution mechanism and the molecule will undergo inversion.