Consider the following chemical equation P MnO4^- (aq) + Q Cl^- (aq) + R H^+ (aq) becomes 2 Mn^2+ (aq) + 8 H2O + S Cl2 (aq) What are the values of P, Q, R and S ? Share with your friends Share 0 Vartika Jain answered this Dear Student, MnO4- + Cl- → Mn2+ + Cl2Step 1: Divide the equation into two half cells:Oxidation half : Cl- → Cl2Reduction half : MnO4- → Mn2+ Step 2: Balance all atoms other than H and OOxidation half : 2Cl- → Cl2Reduction half : MnO4- → Mn2+Step 3: Balance O by adding H2OOxidation half : 2Cl- → Cl2Reduction half : MnO4- → Mn2++4H2OStep 4: Balance H by adding H+Oxidation half : 2Cl- → Cl2Reduction half : MnO4- +8H+→ Mn2++4H2OStep 5: Balance charge by adding electronsOxidation half : 2Cl- → Cl2+2e-Reduction half : MnO4- +8H++5e-→ Mn2++4H2OStep 6: Multiply oxidation half by 5 and reduction half by 2 and add both equations2MnO4-+10Cl- +16H+→ 2Mn2++5Cl2+8H2OHence, P=2, Q=10, R=16 and S=5 0 View Full Answer
