Consider the following iodides : PI3 AsI3 SbI3
102o100.2o99o
The bond angle is maximum in PI3, which is:
(1) due to small size of phosphorus (2) due to more bp- bp repulsion in PI3
(3) due to less electronegativity of P (4) none of these
The correct answer is (4) none of these.
The decrease in bond angle as we go down the group from P to As to ,,Sb, is due to inert pair effect. Due to this,when we go down the group,the tendence of s orbital to participate in hybridisation decrease due to increse in energy difference between s and p orbital as distance from the nucleus increase. Thus,down the group pure p obitals participate in bonding and bond angle decraeses and is close to 90 degrees.
The decrease in bond angle as we go down the group from P to As to ,,Sb, is due to inert pair effect. Due to this,when we go down the group,the tendence of s orbital to participate in hybridisation decrease due to increse in energy difference between s and p orbital as distance from the nucleus increase. Thus,down the group pure p obitals participate in bonding and bond angle decraeses and is close to 90 degrees.