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Consider the parallelogram find the value of x y z

X=80
Y=80[VOA +ASP]
Z=40[V.O.A]
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z=40
​by alternate interior angles.

y=130
by angle sum property

​​x=30

by corresponding angles.
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z=40
?by alternate interior angles.

y=130
by angle sum property

??x=30

by corresponding angles.
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x = 80
y= 80
z= 40
 
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Csss
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x=50
y=60
z=50
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Please find this answer

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Hope it helps you
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ABCD 892
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Anyone please answer the
E right niw
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x=50.z=40.y=60.
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x = 50°
y = 80°
z = 40°
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Y=130
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x=50?
y=60?
z=50 it is correct I think
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ABCD is a parallelogram,
AB II CD AND AD II BC,
AC is the interesting line,
Angle CAD = Angle ACB = 40degree (Alternating angles),
Angle COD =Angle COB = 180
=100 + COB = 180,
COB = 180-100=80,
80 + Y + 40 = 180,
180 - 120 = 60,
100+ACD +X = 180,
180 - 100+30 = 50,
X0
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