Consider the situation where:
 An object is 3 cm (height)
 Mirror is concave with 6 cm focal length.
 Object is placed at the centre of curvature.
Which of the following options are correct?
A. The mirror will produce an image of magnification +1.5.
B. The mirror will produce an image of magnification -1.
C. The mirror will produce an image of magnification +1.
D. The mirror will produce an image of magnification -1.5

Dear Student,
Given,
Mirror is concave mirror of focal length f = 6 cm. Since, the focus lie on the front side of the mirror, using sign conventions, 
f = - 6 cm
Object height, h = + 3 cm
Object distance, u = R = 2f = -12 cm
Let the image distance be v
From mirror equation,
1u+1v=1f1v=1f-1u1v=-16-1-12=-16+112=-2+112=-112v=-12 cm

So, 
Magnification, 
M=image heightObject height=-vu=--12-12=-1Thus,M=-1

So, the correct option is (B) The mirror will produce an image of magnification -1.

Regards

  • 0
What are you looking for?