Consider the two vectors A and B .The magnitude of their sumi .e , /A+B/ , if /A/ is greater than /B/

According to question the sum of two vectors is equal to resultant R
and
 R =A +BR =A +B    (taking mod to both  sides)R2 =A +B2  R =A2+B2+2ABcosθ
here θ is the angle between both vector A and B , but in question  only given 
A > B     which just clears that the magnitude of vector A is greater than magnitude of vector B
if we put the numerical values in the  resultant formula we will get the desired result.

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The magnitude of their sum is| R| = (|A|2+|B|2 + 2 .| A| .| B| . cosθ)(1 / 2 )whereθ is the angle between the vectors A and B .It has no relevance with what is greater of smaller vector .It can applied anywhere.

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