Construct a parallelogram ABCD such that AB =5cm ,BC =3.2cm and angle B=120

We have the following construction-

Step 1 : Draw a line segment of 5 cm as AB.

Step 2 : Draw an arc of 120 deg and cut an arc of 3.2 cm to get point C.

Step 3 : At point A, draw an arc of 60 deg and cut an arc at a distance of 3.2 cm from A to get point D.

Step 4 : Join CD to get the required parallelogram ABCD.