CONSTRUCT A QUADRILATERAL ABCD IN WHICH AB =5.6CM, BC=4 CM,ANGLE A =50 ,ANGLE B=105 , D=80

We know from angle sum property of quadrilateral ,

$\angle$ A  +  $\angle$ B + $\angle$ C   + $\angle$ D  =  360$°$ , So

50$°$  + 105$°$ + $\angle$ C + 80$°$   =  360$°$

$\angle$ C =  125$°$

We follow these steps to construct our quadrilateral ABCD from given information :

Step 1 : Draw line AB  =  5.6 cm

Step 2 : With the help of protractor we form $\angle$ BAX  =  50$°$  and $\angle$ ABY  =  105$°$ .

Step 3 : We take radius of 4 cm and center " B " draw an arc that intersect our line BY at " C " .

Step 4 : Now with the help of protractor we form 125$°$ angle at " C " and angle ray intersect line AX at " D " .

We get our required quadrilateral ABCD :

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