construct a right angled triangle in which base is 4.5 cm and the hypotenuse makes an angle of 30 degree with the base . measure the other sides of the triangle. ​

Dear Student,

Please find below the solution to the asked query:

We follow these steps :

Step 1 :  Draw a line AB  = 4.5 cm

Step 2 : Take any radius ( Less than half of AB ) and center  " A " draw an arc that intersect our line AB at " P " . With same radius and center " P " draw an arc that intersect our previous arc at " Q " . Now with same radius and center " P " and " Q " draw arcs and these arcs intersect each other at " R" . Join AR and extend it to " S " we get line AS .

Step 3 : Take any radius ( Less than half of AB ) and center  " B " draw a semicircle that intersect our line AB at " T " . With same radius and center " T " draw an arc that intersect our semicircle at " U ", Again with same radius and center " U" draw an arc that intersect our semicircle at " V " . Now with same radius and center " U " and " V " draw arcs and these arcs intersect each other at " W" . Join BW and that intersect line AS at " C " .

We get our required right angle triangle ABC , As :



Now with the help of ruler measure other tow sides ( AC and BC )  by yourself .

Hope this information will clear your doubts about topic.

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Regards

  • 3
First draw a line BC as 4.5 cm
Taking C as centre, draw a 60 degree angle and then bisect it so that it is 30 degrees.
Mark it as Y
Now make a right angle with B as centre and mark the line X
Mark the point of intersection of X AND Y as A

Triangle ABC is the required triangle
  • 1
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