Construct a right triangle in which AB = 5.3 cm, BC = 4.6 cm and ∠C = 90°.
Dear Student,
Please find below the solution to the asked query:
We follow these steps to construct right angle triangle ABC .
Step 1 : Draw a line BC = 4.6 cm
Step 2 : Take radius ( Less than half of line BC ) and take center " C " draw a semicircle that intersect our line BC at "P " . Now with same radius and center " P " draw an arc that intersect our semicircle at " Q " . Again with same radius and center " Q " draw an arc that intersect our semicircle at " R " . Now with same radius and center " Q "and " R " draw arcs these arcs intersect each other at " S " .
Step 3 : Join CS and extend it to " T " we get line CT .
Step 4 : Take radius of 5.3 cm and center " B " draw an arc that intersect our line CT at " A " . Join AB . We get our required right angle triangle ABC .
Hope this information will clear your doubts about Constructions.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
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Please find below the solution to the asked query:
We follow these steps to construct right angle triangle ABC .
Step 1 : Draw a line BC = 4.6 cm
Step 2 : Take radius ( Less than half of line BC ) and take center " C " draw a semicircle that intersect our line BC at "P " . Now with same radius and center " P " draw an arc that intersect our semicircle at " Q " . Again with same radius and center " Q " draw an arc that intersect our semicircle at " R " . Now with same radius and center " Q "and " R " draw arcs these arcs intersect each other at " S " .
Step 3 : Join CS and extend it to " T " we get line CT .
Step 4 : Take radius of 5.3 cm and center " B " draw an arc that intersect our line CT at " A " . Join AB . We get our required right angle triangle ABC .
Hope this information will clear your doubts about Constructions.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards