construct a square of side 5cm
and bisect it
can i please have the answer fast? thankyou.
Step (1) : Draw AB = 5 cm
Step (2) : Draw an angle of 90 degree on A.
Step (3) : Draw an angle 90 degree on B.
Step (4) : With A as centre radius 5 cm draw an arc cutting the perpendicular on A.
Step (5) : With B as centre radius 5 cm draw an arc cutting the perpendicular on B.
Step (6) : Join CD.
and hence, ABCD is the required square.
To bisect it, join AC or BD. Thus, square bisect in two equal parts triangle ABC and triangle ADC.