Construct a trapezium ABCD in which AB is parallel to DC having AB=9 cm, CD=5 cm, angle BAD=70 degree , angle DBA=50 degree

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BAD+ADC=180°    Adjacents angles are supplementary in trapezium70°+ADC=180°ADC=110°steps of construction :1 Draw a line segment AB=9 cm .2 Draw a line AP at an angle 70° at point P and  Draw a line BQ at an angle 50° at point Q.3 Line AP and BQ intersects at point D.4 At point draw a line DR at an angle of 110° .5 Taking D as centre , draw an arc of 5 cm , which cuts line DR at point C .6 Join BC .Thus ABCD is the required trapezium .
 
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Plz expert send me the right answer don't send me the similar link as question is different to draw
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