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construct a triangle ABC, bc=5 cm , angle A = 60 degree, Altitude AD=4cm,  

 

Hi!
Here is the answer to the question.
 
Follow the steps to construct the triangle.
Step 1: Draw a line segment BC = 5 cm. Step 2: At B make ∠CBE = 60°. Step 3: Draw BF ⊥ BE. Step 4: Draw the perpendicular bisector of BC meeting BF at 'O'. Step 5: With O as centre and radius equal to OB or OC draw a circle BCK. Step 6: Then the segment BKC contains the angle 60°. Step 7: On the perpendicular bisector GO mark a point 'H' such that GH = 4 cm Step 8: Through H draw AHA′ parallel to BC. Step 9: Join BA and CA.

 

Thus, ABC is the required triangle.
 
Cheers!

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How can construction be shown here?

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yha   if i place my compass on my desktop monitor  the point of the compass can b seen on the othr end of the monitor  i mean  my monitor breaks....

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arey rite the steps if then ...... steps of construction can do. or explain the concept 

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 srry da  i dnt knw  i hv taught mayumi  n i forgot it  ask her...

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srry  i taught maryam  i hv forgotten  ask her bro...

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can u explain it 

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draw BC = 5cm ....a perpendicular to BC - at any point...take the length of the perpendicular 5cm name the point A and joiin AB and AC

 

guess i'm correct

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how to prove that angle A is 60 degrees 

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 SINCE A PERPENDICULAR BISECTOR IS CONSTRUCTED ie THE ALTITUDE     THE ANGLES FORMED WILL AUTOMATICALLY BE 60 DEGREE

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altitude is not a perpendicular bisector and perpendicular bisector is not necessary that it passes frn the vertices 

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 thnkkkkkk u  

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