construct a triangle ABC, when AB=AC, BC=6.0cm and angleB=45.
Here are the steps of construction:
Step 1 : Make a line BC = 6 cm as base of the triangle.
Step 2 : AB = AC, so the angles at B and C will be same.
∴ ∠B = ∠C = 45°
So, make an ∠XBC = 45° at point B.
Step 3 : Now, make an ∠YCB = 45° at point C.
Step 4: Name the point as A, where these two angles meet. (Clearly, ∠A = 90°).
Thus, ∆ABC is the required ∆.
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