construct a triangle abc with ab=5cm, bc=6cm and ac=7cm. then construct another triangle whose sides are 3/5 times the corresponding sides of triangle abc.   thumbs up please. :)

Dear Student,

Please find below the solution to the asked query:

We follow these steps to construct angle ABC   .

Step 1 :  Draw a line BC  = 6 cm and take radius of 5 cm and center " B "  draw an arc and with radius of 7 cm and center " C "  draw an arc that intersect our previous arc at  " A "  .

Step 2 : Join AB and AC , we get triangle ABC

Now We construct another triangle with scale factor $\frac{3}{5}$ , As :
              
Step 1 : Below BC,  draw a line BX  As  $\angle$ CBX is any acute angle and draw three arcs of equal radii on line BX that intersect at X₁ . X₂ , X₃ , X₄ and  X₄ AS :

  BX₁  = X₁ X₂ = X₂ X₃ = X₃ X₄ = X₄ X₅

Step 2 : Join X₅ to C and than draw a line from X₃  as parallel to X₅C that intersect our line BC at C' .

Step 3 : Draw line from C' as parallel to CA that intersect line AB at A'  .



We get triangle A'BC' whose sides are $\frac{3}{5}$ of corresponding sides of triangle ABC .
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