# construct a triangle PQR in PQ = 5cm, QR = 6.5cm, angle Q = 45 degrees

From given information we construct our triangle PQR , As :

Step 1 :  Draw a line PQ  =  5 cm

Step  2 : Take any radius ( Less than half of PQ ) and center " Q "  draw a semicircle that intersect our line PQ at " A " .  With same radius and center " A "  draw an arc that intersect our semicircle at "  B " .Again with same radius and center " B "  draw an arc that intersect our semicircle at "  C " . Now with same radius and take center " B "  and " C "  draw two arcs that intersect each other at " D ".

Step 3 : Join QD  , that line intersect our semicircle at " E " .

Step 4 : Now with same radius and take center "A "  and " E "  draw two arcs that intersect each other at " F ". Join QF an extend it to G  , we get QG .

Step 5 : Take radius of 6.5 cm and center " Q "  draw an arc that intersect our line QG at " R " .

Step 6 : Join PR  , we get our required triangle PQR  . • 2
Sorry I cannot construct but the following steps may help you :-
things needed - a compass , a protractor , a ruler and a sharp pencil
1. draw a line PQ of length 5 cm
2. at Q draw a ray QX making 45 degrees to QP
3. at P put your compass tip and make an arc of radius 6.5 cm cutting the previous ray and forming vertex R
4. join RQ
5. PQR is the required triangle
PLEASE THUMBS UP IF IT HELPS
• 1
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