# construct a triangle PQR in PQ = 5cm, QR = 6.5cm, angle Q = 45 degrees

From given information we construct our triangle PQR , As :

Step 1 : Draw a line PQ = 5 cm

Step 2 : Take any radius ( Less than half of PQ ) and center " Q " draw a semicircle that intersect our line PQ at " A " . With same radius and center " A " draw an arc that intersect our semicircle at " B " .Again with same radius and center " B " draw an arc that intersect our semicircle at " C " . Now with same radius and take center " B " and " C " draw two arcs that intersect each other at " D ".

Step 3 : Join QD , that line intersect our semicircle at " E " .

Step 4 : Now with same radius and take center "A " and " E " draw two arcs that intersect each other at " F ". Join QF an extend it to G , we get QG .

Step 5 : Take radius of 6.5 cm and center " Q " draw an arc that intersect our line QG at " R " .

Step 6 : Join PR , we get our required triangle PQR .

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