Construct a triangle similar to a given triangle ABC such that each of its sides is (5/7)^th of the corresponding side of triangle ABC. It is given that AB = 5cm, BC = 7cm and (angle) /_ABC = 50^o.

1. Draw a line AB = 5 cm.

2. Construct ∠ABC = 50°, such that AB = 5 cm.

3. Join AC to get ΔABC.

4. Draw a line AX making an acute angle with AB and divide it in 7 equal parts.

5. Join X₇B and draw a line passing through X₅ and parallel to X₇B.

6. Let this line intersect the line AB at B'.

7. Now, draw a line passing through B' and parallel to BC, which intersects the extended line AC at C'

8. Thus, ΔAB'C' is the required triangle, which is similar to the given triangle and with sides of the sides of the given triangle.