Construct a triangle whose perimeter is 13.5 and the ratio of three sides is 2:3:4.. Pleaz answer fast expertssss tmrows d exam

let the ratio of sides be 2x , 3x , 4x

2 x + 3 x + 4 x = 13.5  =>  9 x = 13.5

=> x = 1.5
therefore sides will be 2 x = 2 x 1.5 = 03
3 x = 3 x 1.5 = 4.5
4 x= 4 x 1.5 =6

now make any of these sides base then with compass construct the triangle
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Follow the following steps1. Draw a line segment PR=13.5 cm.2. At the point P, draw a ray PQ making any acute angle RPQ with PR.3. On PQ mark 9 (2+3+4) points at equal interval P1, P2,......P9.4. Join P9R.5. Through P2 and P5 draw lines P2A and P2B respectively parallel to P9R intersecting PR at A and B respectively. 6. With A as center and radius AP draw an arc.7. With B as center and BR as radius draw another arc to intersect the arc made earlier.Join AC and BC.I m not an expert but you can trust this answer.read it calmly and you'll get it.all d best
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