Construct a triangle whose sides are 4 cm,6 cm and 8 cm and bisect the smallest angle.Measure each part
Answer :
We follow these steps :
Step 1 : Draw a line AB = 8 cm
Step 2 : Now take radius of 4 cm and center " A " draw an arc . And take radius of 6 cm and center " B " draw an arc that intersect our previous arc at " C " .
Step 3 : Join CA and CB , we get required triangle ABC .
Now we measure all internal angles and we get ABC is smallest angle , So we bisect that , As :
Step 4 : Take any radius ( Less than half of AB ) and center " B " draw an arc that intersect our line AB at " P " and line BC at " Q " .
Step 5 : With same radius and center " P " and " Q " draw arcs these arcs intersect at " R " .
Step 6 : Join BR and extend BR that line intersect AC at " D " .
Now we can easily measure each angles and sides . With the help of protector and scale .
We follow these steps :
Step 1 : Draw a line AB = 8 cm
Step 2 : Now take radius of 4 cm and center " A " draw an arc . And take radius of 6 cm and center " B " draw an arc that intersect our previous arc at " C " .
Step 3 : Join CA and CB , we get required triangle ABC .
Now we measure all internal angles and we get ABC is smallest angle , So we bisect that , As :
Step 4 : Take any radius ( Less than half of AB ) and center " B " draw an arc that intersect our line AB at " P " and line BC at " Q " .
Step 5 : With same radius and center " P " and " Q " draw arcs these arcs intersect at " R " .
Step 6 : Join BR and extend BR that line intersect AC at " D " .
Now we can easily measure each angles and sides . With the help of protector and scale .