Construct a triangle XYZ in which  angleY = 30 degree, angle Z = 90 degree, xy + yz + zx = 11cm.
.Is it possible to  have a triangle like this without decimals considering the Pythagorean theorem??

plz answer

  • -6
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.
 
 
The below given steps will be followed to construct the required triangle.
Step I: Draw a line segment AB of 11 cm.
(As XY + YZ + ZX = 11 cm)
Step II: Construct an angle, ∠PAB, of 30° at point A and an angle, ∠QBA, of 90° at point B.
Step III: Bisect ∠PAB and ∠QBA. Let these bisectors intersect each other at point X.
Step IV: Draw perpendicular bisector ST of AX and UV of BX.
Step V: Let ST intersect AB at Y and UV intersect AB at Z.
Join XY, XZ.
ΔXYZ is the required triangle.
 
  • 38

Step I: Draw a line segment AB of 11 cm.

(As XY + YZ + ZX = 11 cm)

Step II: Construct an angle, ∠PAB, of 30� at point A and an angle, ∠QBA, of 90� at point B.

Step III: Bisect ∠PAB and ∠QBA. Let these bisectors intersect each other at point X.

Step IV: Draw perpendicular bisector ST of AX and UV of BX.

Step V: Let ST intersect AB at Y and UV intersect AB at Z.

Join XY, XZ.

ΔXYZ is the required triangle

  • 18

yfrhgh dfbd

  • -6

How XY+YZ+ZX=AB

  • -6
diagram

 
  • -6
Can u answer the JUSTIFICATION for this sum . Please anybody try.... I need it...
  • -5
can u tell how to write the justification for this question
  • -6
tnq u sooo much dis helped me a lot
  • -5
tnx a lot
 
  • -3
Thanks a lot
  • -1
What are you looking for?