Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.

A rough sketch of the required triangle is as follows.

The steps of construction are as follows.

(i) Draw a line segment BC of length 7.5 cm.

(ii) At point C, draw a ray CX making 60º with BC.

(iii) Taking C as centre, draw an arc of 5 cm radius. It intersects CX at point A.

(iv) Join A to B to obtain triangle ABC.

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