Construct an isosceles triangle whose altitude is 4.5cm and vertex angle is 70?

Dear Student,

1. Draw a line segment XY using a ruler of any length.



2. Take a point M on line XY and draw a perpendicular line MP such that MP ⊥ XY; use protractor to measure the angle 90°.



3. Now, with M as centre draw a circle or semicircle or an arc of radius 4.5 cm cutting MP at A using a compass and a ruler.




on XY such that, ∠MAB = 35°  and ∠MAC = 35° . Measure the angles using a protractor.



Thus, ABC is the required isosceles triangle.

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