Construct an isosceles triangle whose altitude is 4.5cm and vertex angle is 70?
Dear Student,
1. Draw a line segment XY using a ruler of any length.
2. Take a point M on line XY and draw a perpendicular line MP such that MP ⊥ XY; use protractor to measure the angle 90°.
3. Now, with M as centre draw a circle or semicircle or an arc of radius 4.5 cm cutting MP at A using a compass and a ruler.
4. 
on XY such that, ∠MAB = 35° 
and ∠MAC = 35° 
. Measure the angles using a protractor.
Thus, ABC is the required isosceles triangle.
regards.