# Construct an isosceles triangle whose altitude is 4.5cm and vertex angle is 70?

1. Draw a line segment XY using a ruler of any length.

2. Take a point M on line XY and draw a perpendicular line MP such that MP ⊥ XY; use protractor to measure the angle 90°.

3. Now, with M as centre draw a circle or semicircle or an arc of radius 4.5 cm cutting MP at A using a compass and a ruler.

4.

on XY such that, ∠MAB = 35° and ∠MAC = 35° . Measure the angles using a protractor.

Thus, ABC is the required isosceles triangle.

regards.

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