Construct an right triangle when one side is 4.5cm and difference of other and hypotenuse is 6.5cm .

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Please find below the solution to the asked query:
$$\begin{gathered} \mathrm{Step}1=\mathrm{Draw} \mathrm{line} \mathrm{segment} \mathrm{AB} \mathrm{of} 4.5 \mathrm{cm} \\ \mathrm{Step}2=\mathrm{Draw} \mathrm{a} \mathrm{ray} \mathrm{AX} \mathrm{making} 90° \mathrm{with} \mathrm{AB} \\ \mathrm{Step}3=\mathrm{Cut} \mathrm{the} \mathrm{line} \mathrm{segment} \mathrm{AD} \mathrm{of} 6.5 \mathrm{cm} \mathrm{from} \mathrm{ray} \mathrm{AX} \\ \mathrm{Step}4=\mathrm{join} \mathrm{DB} \mathrm{and} \mathrm{make} \mathrm{an} \mathrm{angle} \mathrm{DBY} \mathrm{same} \mathrm{as} \mathrm{ADB} \\ \mathrm{Step}5=\mathrm{Let} \mathrm{BY} \mathrm{intersect} \mathrm{AX} \mathrm{at} \mathrm{C} \mathrm{join} \mathrm{AC} , \mathrm{BC} \\ \mathrm{Triangle} \mathrm{ABC} \mathrm{is} \mathrm{required} \mathrm{triangle} \end{gathered}$$

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