construct angle abc in which BC = 6 2 CM ,ACB is equal to 50 degree AB+ AC 9 8 - Maths - Congruency of Triangles

Question

construct angle abc in which BC = 6 2 CM ,ACB is equal to 50 degree
AB+ AC 9 8 centimetre

Mohammed Irfan Khan · Accepted Answer

Dear Student

Steps of Construction:1
 Draw base BC of length 6 2 cm2
 Draw ∠ACB=50° with the help of protractor
3  Open the compass to length AB+AC=9
8 cm
    From point C as a center, cut an arc on ray CX
    Let the arc intersect CX at D4
 Joib BD 5
 Now, we will draw perpendicular bisector of BD
6
 Mark point A where perpendicular bisector intersects CD
7  Join AB
<img alt="" src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/ck_5cbf0bc46d57c%20jpg"
style="width: 1018px; height: 382px;">
∴ ∆ABC is the required triangle
Regards

construct angle abc in which BC = 6.2 CM ,ACB is equal to 50 degree AB+ AC 9.8 centimetre