construct triangle ABC , BC= 6.5 cm, AB=4.5 and angle ACB =60. construct a triangle similar to the given triangle whose sides are 4+5 the sides of given triangle

Dear Student,

Please find below the solution to the asked query:

We follow these steps to construct angle ABC   .

Step 1 :  Draw a line BC = 6.5 cm  .

Step 2 :  Now take any radius ( Less than half of BC ) and take center  " C "  draw an arc that intersect our line BC at  " P " , With same radius and center is " P "  draw another arc that intersect our previous  arc at "  Q " .

Step 3 :    Join CQ and extend it to D

Step 4 :  Take radius = 4,5 cm and center "  B "  we draw an arcs that intersect our line BD at "  A "  Now we join AB , and get triangle ABC .

Now We construct another triangle with scale factor $\frac{4}{5}$ , As :
              
Step 5 : Draw a line CX  As  $\angle$ BCX is any acute angle and draw five equal radius arc on line CX that intersect at X₁ . X₂ , X₃ , X₄ and X₅ AS :

  CX₁  = X₁ X₂ = X₂ X₃ = X₃X₄ = X₄X₅

Step 6 : Join X₅ to B and than draw a line from X₄  as parallel to X₅B that intersect our line BC at B' .

Step 7 : Draw line from B' as parallel to AB that intersect line AC at A'  .



We get triangle A'B'C whose sides are $\frac{4}{5}$ of corresponding sides of triangle ABC .

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