[cos50 / 2sin40] + [4(cosec^2 59 - tan^2 31) / 3 tan^2 45] - [two third * tan12tan78.sin90}

sorry i couldnt put the degrees

Question

[cos50 / 2sin40] + [4(cosec^2 59 - tan^2 31) /
3 tan^2 45] - [two third * tan12tan78 sin90}
sorry i couldnt put the degrees

Komal Singh · Answer

[cos50 / 2cos50 ] + [4(sec231 -tan231) /3
tan245] - [2/3 x cot78 tan78 sin90]
= 1/2 + 4/3 - 2/3
= 3+ 8 -4 /6
= 7/6
HOPE THIS HELPS