cos6x = 32cos6x-48cos4x+18cos2x-1
cos6x = cos2(3x)
= 2cos2 3x -1
also cos 3x = 4cos3x - 3cosx..so putting the value ......
=2=(4cos3x - 3cosx)2 - 1
=2(16cos6x + 9cos2x - 24cos4x) -1
32cos6x + 18cos2x - 48cos4x - 1
cos6x = 32cos6x-48cos4x+18cos2x-1
cos6x = cos2(3x)
= 2cos2 3x -1
also cos 3x = 4cos3x - 3cosx..so putting the value ......
=2=(4cos3x - 3cosx)2 - 1
=2(16cos6x + 9cos2x - 24cos4x) -1
32cos6x + 18cos2x - 48cos4x - 1