cos6x = 32cos6x-48cos4x+18cos2x-1

  cos6x = cos2(3x)

  = 2cos2 3x -1

  also cos 3x = 4cos3x - 3cosx..so putting the value ......
=2=(4cos3x - 3cosx)2 - 1

=2(16cos6x + 9cos2x - 24cos4x) -1

32cos6x + 18cos2x - 48cos4x - 1

  • 65

the formula is 2cos2x +1

and 1-2sin2x

  • -14

plz verify your answer

  • -13
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