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if one root of the quadratic equation is 7x2 + kx + 7 = 0 is 1/7 then find the value of k

Experts, please give an answer don't provide links

THANKS

Now,

7(1/7)^2+k(1/7)+7=0

7(1/49)+k/7+7=0

1/7+k/7+7=0

1+k+49=0 [By taking 7 as LCM]

k=-50

=Hence, the required value of k is -50.

{You can also verify your answer by putting the value of k in the given equation.}

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