Current i = 2.5A flows along a circle x^2+y^2=9cm^2 . Magnetic field at point(0,0,4) is? Share with your friends Share 6 Rajesh K Nimat answered this Dear student Magnetic field on the axis of circular loopB=μ04π×2πiR2(R2+z2)3/2B=10-7×2π×2.5×32×10-4125×10-6k^B=(36π×10-7 T) k^Regards 6 View Full Answer