d area of a rectangular feild is (a2-19a+90) sq. units. find d width of d rectangle if its length is (a-9) units......

Given : Length of the rectangle is (a – 9) units.

and area of rectangle = (a2 – 19a + 90) sq. units

Now we know that

Area = Length × Width

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Ok

Area Of Rectangle = Length* Breadth

Now a2-19a+90 = a-9*Breadth

Breadth = a2-19a+90/a-9

a2-19a+90 We Have To Factorize This Expression

a2-9a-10a+90

a(a-9) - 10(a-9)

(a-10)(a-9)

Now Lets SOlve It

Breadth = (a-10)(a-9)/(a-9)

Now a-9 Get Cancelled With Each Other

Breadth = a-10 sq units

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Ok

Area Of Rectangle = Length* Breadth

Now a2-19a+90 = a-9*Breadth

Breadth = a2-19a+90/a-9

a2-19a+90 We Have To Factorize This Expression

a2-9a-10a+90

a(a-9) - 10(a-9)

(a-10)(a-9)

Now Lets SOlve It

Breadth = (a-10)(a-9)/(a-9)

Now a-9 Get Cancelled With Each Other

Breadth = a-10 sq units

 

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