De-broglie wavelength associated with an electron accelerated through a potential difference V is lambda. , what will b its wavelength , when accelerating potential is increased to 4V.

Here, why cant we use the formula '' lambda= 1.22/root V '' and this formula is applicable in what type of quests.?

We know for electron,
λ=12.25 AoV  ..............(1)for potential difference 4Vλ'=12.25 Ao4V=1212.25 AoV=12λ
Hence wavelength become half of initial wavelength.

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you can use the formula here and you will get almost the very same answer as you will get from the formula


You can check with both formulas and answer should match.

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