de Broglie wavelength of electron in second orbit of Li2+ will be equal to de broglie wavelength of electron in (A)n=3 of H-atom (B)n=4 of C5+ ion (C)n=6 of Be3+ ion (D)n=3of He+ ion Answer is (B) No Links Please !! Please solve and explain !! Share with your friends Share 13 Shivam Aggarwal answered this Please find your answer 6 View Full Answer