Dear Expert, Please explain how we can get, 7/9[10+100+1000+...(m+1) term-(1+1+1...m+1 term...+1] =7/9[{10(10m+1-1)/9}-m+1] Share with your friends Share 0 Lovina Kansal answered this Dear student There is a little bit correction in the solutionInstead of 7910+100+1000+...+(m+1) term-1+1+1+...+m+1 times....+1It should be 7910+100+1000+...+(m+1) term-1+1+1+...+m+1 timesConsider,10+100+1000+...+(m+1) termClearly, it is a GP with first term, a=10 and Common ratio,r=10010=10So,10+100+1000+...+(m+1) term=1010m+1-110-1 Sum of finite GP=arn-1r-1=1010m+1-19Consider,1+1+1+...+m+1 times=m+1So, 7910+100+1000+...+(m+1) term-1+1+1+...+m+1 times=791010m+1-19-m+1 Regards 0 View Full Answer
