Dear experts plzz clarify!!!!!

Dear Student!

Here is the answer to your query.

Let B be the building and A be the fire.

Given : P and Q are 2 fire stations 30 km apart.

Let the height of AB be h km

and PB = x km. then BQ = (30 – x) km

also ∠APB = 60° and ∠AQB = 45°

In ΔABP

$\tan 60 ° = \frac{AB}{PB} \Rightarrow \sqrt{3} = \frac{h}{x} \Rightarrow h = x \sqrt{3} ... (1)$

In ΔABQ