DEFG is a quadrilateral such that diagonal DF divides it into two parts of equal areas . Prove that diagonal DF bisects GE also .

Consider the diagram below:
 


Let GA, EB pe perpendiculars on DF from G, E respectively.Given:ar(DEF)=ar(DGF)12(DF)(GA)=12(DF)(EB)GA=EB  -------------(1)Also, GAO=EBO=90   -----(2)Further, AOG=BOE (vertically opposite angles)Now, AGO=180-GAO-AOGSimilarly, BEO=180-EBO-BOETherefore, AGO=BEO  ------(3)Using (1), (2), (3), we can see that GOABOE (by ASA property)Hence, GO=EO.

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