Degree of dissociation of 0 1 M HCN solution is 0 01% its ionisation constant would be a)10-3 - Chemistry - Equilibrium

Question

Degree of dissociation of 0 1 M HCN solution is 0 01% its
ionisation constant would be
a)10-3 b)10-5
c)10-7 d)10-9

Tinku Jangra · Accepted Answer

HCN is a weak acid, So, the equilibrium constant will be calculated
by Ostwald dilution law
Initial concentration = 0
1 MDegree of dissociation = 0
01% = 10-4                                                                HCN        ⇌      H+           +      CN-Initial concentration at time, t=0      0
1M                     0                         0At time t=teq
, concentration       0
1(1-10-4)          0
1×10-4     0
1× 10-4Keq=[H+][CN-][HCN] = 0
1×10-4×0 1×10-40 1×(1-10-4)=10-9

Degree of dissociation of 0.1 M HCN solution is 0.01%. its ionisation constant would bea)10-3 b)10-5 c)10-7 d)10-9

Degree of dissociation of 0.1 M HCN solution is 0.01%. its ionisation constant would be
a)10^-3b)10^-5
c)10^-7 d)10^-9